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Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,Because nums[0] + nums[1] = 2 + 7 = 9,return [0, 1].

思路：两个数的和一定（target），如果一个其中一个数字固定，那另一个数字也就固定了。

所以我用for循环，每次先固定一个数，再用index方法寻找另一个。（不能重复）

class Solution(object):    def twoSum(self, nums, target):        """        :type nums: List[int]        :type target: int        :rtype: List[int]        """                 for i,val in enumerate(nums):            retarget = target - val            if retarget in nums and nums.index(retarget) != i:                j = nums.index(retarget)                return [i,j]

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